\sum_{n=1}^\infty \frac{n!}{n^n}x^n
\] diverges when $|x|$ is the radius of convergence $e$. In fact, we can show that \[
n!\brac{\frac{e}{n}}^n\to \infty
\] by Stirling's Formula (in the simplest form), which is the following asymptotic result:
Theorem. We have $\dis n!\sim \sqrt{2\pi n} \brac{\frac{n}{e}}^n$ as $n\to \infty$.